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5 ⨯ 5

| \begin{matrix} - 4 & 2 \\ - 5 & 2 \end{matrix} |

\frac{1}{1 + 4 x^{2}} ⅆ x

5 ⨯ 5

\frac{3}{2} \div \frac{1}{4}

10^{- 2}

\cos (0.52)

| \begin{matrix} - 4 & 2 \\ - 5 & 2 \end{matrix} |

- x + 4 = 3

\sqrt{x + 4} = 5

| x + 5 | = 7

x^{2} - 10 x = 0

x^{3} + 2 x = 0

\frac{1}{x - 1} + \frac{- 2}{x + 1} = \frac{6}{x^{2} - 1}

5^{x} = 478

\log_{8} {(x)}^{4} = 12

4 \cos^{2} (x) - 2 = 0

[\begin{matrix} 1 & - 5 \\ 0 & - 1 \end{matrix}] X = [\begin{matrix} 4 & 0 \\ - 5 & 5 \end{matrix}]

\frac{ⅆ}{ⅆ x} (5 x)

\frac{ⅆ}{ⅆ x} \cot (- x)

\frac{ⅆ}{ⅆ x} (6 e^{2 x})

\int (- 10) ⅆ x

\frac{1}{1 + 4 x^{2}} ⅆ x

\int (5 e^{x}) ⅆ x

\int_{- 6}^{0} (6 x) ⅆ x

\int_{0.3}^{0.6} \cos (3 x) ⅆ x

\int_{- 4}^{2} (e^{2 x}) ⅆ x

\frac{ⅆ y}{ⅆ x} + y = 2

\frac{ⅆ^{2} y}{{ⅆ x}^{2}} - y = 2